Answer:
The player with the most runs had a rush of 1,240 yards
Step-by-step explanation:
In this question, we are asked to calculate the number of yards that was rushed by one of two person given their combined run and an extra information.
Firstly, let the person that had the smaller number of rush have a rush of x rushes. The second person has a rush of 4 times the other. This makes a number of 4x rushes
By adding both together, we have a total of 1550 yards
Mathematically, this means that x + 4x = 1550
5x = 1550
x = 1550/5 = 310 rushes
The second player had a rush of 4x and that is 4 * 310 = 1,240 rushes
2+2=4
a^2+b^2=c^2
15^2-4^2
=225-16
=209
|
|__x_- 4___________ 2x³/2x² =x
2x² + 2x +3 | 2x³ - 6x² +7x +3
- (<span>2x³ +2x² +3x)
</span> -8x² +4x +3 -8x²/2x² = -4
<span>-(-8x² -8x -12)
</span> 12x +15
(x-4) + (12x +15)/(2x² + 2x +3)
Answer:
Ok y= 2x + b
b referring to any number less than -2 and more than -2
so y=2x+4 can work
Step-by-step explanation:
parallel lines in slope-intercept form have the same slope, i.e. the same 'm' value or coefficient of <em>x</em><em> </em> but different interceptions
