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2 years ago

9) Let X-2, x, x+3 be the first 3 terms of a geometric sequence. FInd the value of x.. PLEASE HELP

1 answer:

7 0

Hello,

Let's r the ration

We suppose x ≠0

x=r*(x-2)==>r=x/(x-2)

x+3=r*x==> (x+3)/x=x/(x-2)==>(x+3)(x-2)=x²
==>x²+3x-2x-6=x² ==>x-6=0==>x=6

x-2=6-4=4
x=6
x+3=6+3=9
6=4*3/2
9=6*3/2

Ration 3/2
First term: 4

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miv72 [106K]

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Distribute the -6 into the parentheses:

-86 = (-6 * -3p) + (-6 * -3) - 5p

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Simplify:

-86 = 13p + 18

Subtract both sides by 18:

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Divide both sides by 13:

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Step-by-step explanation:

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2 years ago

What is the missing coefficient of the x-term of the product (-x-5)2 after it has been simplified?

LiRa [457]

Answer:

The missing coefficient of the x-term of the product (-x-5)2 is 10.

Step-by-step explanation:

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Through whole square formula.

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In a triangle , the measure of the first angle is twice the measure of the second angle. The measure of the third angle is 100 m

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Answer:

The three unknown angles X, Y , and Z are:

X = 40, Y = 20, and Z = 120

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Let's name X the measure of the first angle, Y the measure of the second one, and Z that of the third one.

Then we can create the following equations:

X = 2 Y

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