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Mandarinka [93]
3 years ago
7

9) Let X-2, x, x+3 be the first 3 terms of a geometric sequence. FInd the value of x.. PLEASE HELP

Mathematics
1 answer:
adoni [48]3 years ago
7 0
Hello,

Let's r the ration

We suppose x ≠0

x=r*(x-2)==>r=x/(x-2)

x+3=r*x==> (x+3)/x=x/(x-2)==>(x+3)(x-2)=x²
==>x²+3x-2x-6=x² ==>x-6=0==>x=6

x-2=6-4=4
x=6
x+3=6+3=9
6=4*3/2
9=6*3/2

Ration 3/2
First term: 4

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Answer:

See below

Step-by-step explanation:

<u>Given function:</u>

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m represents the domain and D represents the range of the function, therefore m = x, D = y

<u>Filling in the table:</u>

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false

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Find the sample variance for the data 9,12,9,14,6. Round the answer to one decimal place. Sample variance
Feliz [49]

Answer:

9.5

Step-by-step explanation:

Find the sample variance for the data 9,12,9,14,6. Round the answer to one decimal place. Sample variance.

Step 1

We find the Mean of the numbers

Mean = Sum of terms/ Number of terms

Mean = 9+12+9+14+6/5

= 50/5

= 10

Step 2

We find the sample variance

Formula =

(x - Mean)²/n - 1

n = 5

= (9 - 10)²+(12 -10)²+(9- 10)²+(14-10)²+(6-10)²/5 - 1

= 1+ 4+ 1+ 16+16/5 - 1

= 38/5 - 1

= 38/4

= 9.5

Therefore, Sample variance = 9.5

3 0
3 years ago
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