What important piece of software controls the computer's hardware and software resources?

Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth

telo118 [61]

Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}

So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.

4 0

3 years ago

How do i work on code with someone else? i use visual studio code. me and a friend wanna make a game together with code. how do

Art [367]

Answer:

You can use Repl.it.com......It's best for practising coding languages...

7 0

3 years ago

Weakness in software can be more quickly uncovered and exploited with new software tools and techniques.

grandymaker [24]

False because it might damage it more but if it was recommended by lots of people i mean the software then its true

6 0

3 years ago

Write a date transformer program using an if/elif/else statement to transform a numeric date in month/day format to an expanded

boyakko [2]

I wrote it in Python because it was quick so i hope this is helpful

Answer:

date = input('Enter Date: ')

split_date = date.split('/')

month = split_date[0]

day = split_date[1]

if month == '1':

english_month = 'January'

spanish_month = 'Enero'

elif month == '2':

english_month = 'February'

spanish_month = 'Febrero'

elif month == '3':

english_month = 'March'

spanish_month = 'Marzo'

elif month == '4':

english_month = 'April'

spanish_month = 'Abril'

elif month == '5':

english_month = 'May'

spanish_month = 'Mayo'

elif month == '6':

english_month = 'June'

spanish_month = 'Junio'

elif month == '7':

english_month = 'July'

spanish_month = 'Julio'

elif month == '8':

english_month = 'August'

spanish_month = 'Agosto'

elif month == '9':

english_month = 'September'

spanish_month = 'Septiembre'

elif month == '10':

english_month = 'October'

spanish_month = 'Octubre'

elif month == '11':

english_month = 'November'

spanish_month = 'Noviembre'

elif month == '12':

english_month = 'December'

spanish_month = 'Diciembre'

US_English = f'{english_month} {day}'

International_Spanish = f'{day} {spanish_month}'

print(f'US English Form: {US_English}')

print(f'International Spanish Form: {International_Spanish}')

Input:

3/5

Output:

US English Form: March 5

International Spanish Form: 5 Marzo

Explanation:

You start by taking input from the user then splitting that at the '/' so that we have the date and the month in separate variables. Then we have an if statement checking to see what month is given and when the month is detected it sets a Spanish variable and an English variable then prints it to the screen.

Hope this helps.

7 0

3 years ago

Why won't my ads load brainly? Is anyone else having this problem? Brainly company or whoever you are that is running this websi

djverab [1.8K]

No I have not had that do that to me before It has always loaded my ads and sent me right back to the answer

7 0

3 years ago

Read 2 more answers