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faltersainse [42]
2 years ago
8

Calculate the simple interest on each amount and the total amount at the end.

Mathematics
1 answer:
Butoxors [25]2 years ago
5 0
Attached is a picture of my answers.

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If sal can fill a case of water at the rate of 223 case/min how many cases can he fill in 35 minutes
charle [14.2K]

Answer:

7805 cases of water

Step-by-step explanation:

  • just multiply 223 by 35 minutes
8 0
3 years ago
The length of a rectangle is 55 inches more than the width. the perimeter is 4242 inches. find the length and the width of the r
faust18 [17]
L = W + 55
2L + 2W = 4242

L + W = 2121
(W + 55) + W = 2121
2W + 55 = 2121

W = 1033 inches           L = 1088 inches
6 0
2 years ago
What is the solution to the inequality?<br><br> −4(x−6)≤−2x+6
Kipish [7]
-4(x-6) ≤ - 2x+6
-4x-24≤ -2x+6
+2x +2x
-2x-24≤+6
+24 +24
-2x ≤ 30
Divide both sides by -2
and you get....
x ≥ -15
You switch the inequality sign because you're dividing by a negative.
I hope all is well, and you pass! Good luck, rockstar! (:
3 0
3 years ago
Given y = log3(x + 4), what is the domain?
dem82 [27]
For a logarithmic function, we have a restriction on the domain.
Since log(0) isn't defined, we say that there is an asymptote at x = 0.
Thus, for the regular logarithmic function y = log(x), x > 0.

We can then say (x + 4) > 0, since that's when the function of a logarithm is defined as.
x + 4 > 0
x > -4

Thus, the domain of the logarithmic function is x > -4, where x is a real integer.
5 0
2 years ago
Read 2 more answers
During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be
rusak2 [61]

Answer:

The distance between the astronomers and the moon was 7.56*10^{8] meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

v = \frac{d}{t}

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that t = 2.52.

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that v = 3*10^{8}m/s.

We have to find d. So:

v = \frac{d}{t}

d = vt

d = 3*10^{8}*2.52

7.56*10^{8]

The distance between the astronomers and the moon was 7.56*10^{8] meters.

7 0
3 years ago
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