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lukranit [14]
2 years ago
10

On Saturday morning Briana and her friends walked 1.35 miles. What is the distance as a decimal

Mathematics
1 answer:
padilas [110]2 years ago
3 0

Answer:

1.35 miles is the distance walked in decimal form

Step-by-step explanation:

1 (decimal) 35

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Four times a number increased by 3 is -89
sp2606 [1]

Answer:

-21.5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
4 years ago
Replace ? with =, >, or < to make the statement true. 12 ÷ 4 + 13 ? 2 + 22 ÷ 2
bogdanovich [222]

Answer:

>

Step-by-step explanation:

On the left side, we divide first: 12/4=3

On the left side, we get 3+13, which equals 16.

On the right side, we also divide first: 22/2=11

On the right side, we get 11+2, which equals 13.

We know that 16 is larger than 13, so  

12 ÷ 4 + 13 > 2 + 22 ÷ 2

Hope this helps!

8 0
3 years ago
The perimeter of Square three is 20.4 square units in the perimeter of square two is 27.2 square units what is the area of squar
koban [17]

Answer:

a=554.88

Step-by-step explanation:

20.4*27.2=

3 0
3 years ago
When multiplied together, which two polynomials equal ab3+2a2b2? Select the two correct answers.
fomenos
The answer is 2) ab2 that would be ur answer
5 0
3 years ago
Read 2 more answers
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