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rjkz [21]
3 years ago
10

Ghj,aedhf;oeskz.jfesl;zfjeghkljrdsoxdhrgdklwrsd

Mathematics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

30/(5+7)

Step-by-step explanation:

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Which statement is not true about histograms
Eduardwww [97]

Answer:

d

Step-by-step explanation:

d is not true because width and thickness doesn't matter

8 0
3 years ago
Reggie has a rectangular piece of paper that is 12 inches long and 7 inches wide. He is going to cut the paper from corner to co
neonofarm [45]

A property from geometry states that rectangles have congruent opposite sides. Thus, no matter which diagonal Reggie cuts, it still has the same lengths. Since it's a rectangle and we cut from corner to corner, we create a right triangle. See the picture below:

<u>___________12 inches_______</u>

7 |

i |

n |

Because it's a rectangle, it won't matter which corner we cut. But if we fold at the cut lines, we would make an in the rectangle's center.

The cut line and two sides make a right triangle. One leg is 12, one leg is 7, and we need to find the third side. The Pythagorean Theorem - sum of the squares of the legs equals the square of the hypotenuse - is applied.

Let S = the length of the side from corner to corner

S² = 12² + 7²

S² = 144 + 49

S² = 193

S = √193 or -√193

Because we are dealing with lengths, we only want positive numbers. -√193 is not used. Thus S = √193

S = √193 = 13.8924439894

S = 18.92 (rounded to two places)


Thus, Reggie will cut 18.92 inches of paper.

5 0
3 years ago
Graph the function f(x)=−13x+1.
pogonyaev

Graph each points:

f(x) = -13x + 1

when x = 0, y = 1

f(0) = -13(0) + 1

f(0) = 0 + 1

f(0) = 1

when x = 1, y = -14

f(1) = -13(1) + 1

f(1) = -13 + 1

f(1) = -14

when x = 2, y = -25

f(2) = -13(2) + 1

f(2) = -26 + 1

f(2) = -25

etc.

Graph each point and connect them.

7 0
3 years ago
What does x=? I know it is vertical
Rudik [331]
The angles are <span>supplementary
</span>
7x + x + 20 = 180
8x = 160
x = 20
6 0
3 years ago
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IRINA_888 [86]
C on the 1st one. A on 2nd one A on 3rd
6 0
3 years ago
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