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Lilit [14]
3 years ago
6

Simplify:

Mathematics
2 answers:
Kobotan [32]3 years ago
6 0

1 \frac{5}{6} \times 2 \frac{3}{4} + 1 \frac{5}{6}  \times 1 \frac{3}{4} \\  |1 \frac{5}{6}(2 \frac{3}{4} + 1 \frac{3}{4} )  |  \\  | \frac{11}{6}( \frac{11}{4}  +  \frac{7}{4})  |  \\  | \frac{11}{6} \times (11 +  \frac{7}{4})  |  \\  | \frac{11}{6} \times  \frac{18}{4}  |  \\  | \frac{33}{4} |  \\  |8 \frac{1}{4} |

<em>hope</em><em> </em><em>it'll help you</em><em>.</em><em>.</em><em>.</em>

Xelga [282]3 years ago
5 0

1 \times \frac{5}{6}  \times 2 \times \frac{3}{4}  +  1 \times \frac{5}{6} \times 1 \times \frac{3}{4}

= \frac{11}{6}  \times  \frac{11}{4}   +  \frac{11}{6}  \times  \frac{7}{4}

Multiply them and after we'll add them

=  \frac{121}{24}  +  \frac{77}{24}

Use L.C.M

=  \frac{198}{24} answer

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The coordinates of ∆ABC are A(-3, 2), B(5, 8) &amp; C(11, 0). Which type of triangle is ∆ABC? Select All that apply.
stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(5-(-3))^2+(8-2)^2}

AB=\sqrt{(8)^2+(6)^2}

AB=\sqrt{64+36}

AB=\sqrt{100}

AB=10

Similarly,

BC=\sqrt{(11-5)^2+(0-8)^2}

BC=\sqrt{(6)^2+(8)^2}

BC=\sqrt{36+64}

BC=\sqrt{100}

BC=10

And,

AC=\sqrt{(11-(-3))^2+(0-2)^2}

AC=\sqrt{(14)^2+(-2)^2}

AC=\sqrt{196+4}

AC=\sqrt{200}

AC=10\sqrt{2}

Two sides of the triangle are equal, i.e., AB=BC. So, the triangle is an isosceles triangle.

Sum of square of two smaller side is

AB^2+BC^2=10^2+10^2

AB^2+BC^2=100+100

AB^2+BC^2=200

AB^2+BC^2=AC^2

Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

7 0
3 years ago
Solve by multiplication and addition. Show each step of your work.
Kitty [74]

Answer:

X= -8

Step-by-step explanation:

only if you are supposed to add the equations at the end

4 0
3 years ago
Read 2 more answers
Can you please help me solve these systems?
sveta [45]
<span>1)
11x+5y=20
2x+5y=-25

multiply the second equation by - 1 and add the result with the first equation:

11x + 5y = 20
- 2x - 5y = 25
-------------------
9x = 45

=> x = 45 / 9

=> x = 5

Replace in </span><span>2x+5y=-25

=> 2(5) + 5y = - 25

5y = - 25 - 10

5y = - 35

y = - 35 / 5

y = - 7


2)

3x+7y=-21

3x-7y=63</span>

Add the two equations:

3x + 3x + 0 = - 21 + 63

6x = 42

=> x = 42 / 6

=> x = 7

Replace in <span>3x-7y=63

3(7) - 7y = 63

=> 7y = 21 - 63

=-> 7y = - 42

=> y = - 42 / 6

=> y = - 7</span>
5 0
4 years ago
4log(2) x + log(2)5 = log(2)405
Anna71 [15]

Answer:

3/2

Step-by-step explanation:

6 0
3 years ago
The lesson is 19.2 Angles in inscribed Quadrilaterals
alexdok [17]

Answer:

m<R=44.9,m<S=56.9,m<T=44.9,m<U= 32.9.

Step-by-step explanation:

When two chords are equal then the measure of the arcs are equal.

Chord RU= Chord UT

Or , m arc RU= m arc UT,

3z-4=x+2z+7   Or             z=x+11

Chord RS=Chord ST ,

m arc RS=m arc ST=3x+5

Sum of m arc in a circle =360 degrees.

Or ,

3x+5+3x+5+3z-4+x+2z+7=360

7x+5z+13=360

Substituting z=x+11

7x+5(x+11)+13=360

7x+5x+55+13=360

12x+68=360

12x=292,x=24.3

z=x+11=11+24.3=34.3

m arc RU=marc UT= 3z-4=3(24.3)-4=69

m arc RS =marc ST= 3x+5=3(24..3)+5=77.9

m<R= (marc UT+ m  arc ST)÷2

m<R=(69+77.9)÷2=73.45

m<S= (m arc RU+m arc UT)÷2

m<S= (69+69)÷2=69

m<T=(m arc RU+m arc RS)÷2=73.45

m<U=(m arc RS+m arc m arc ST)÷2=77.9








4 0
4 years ago
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