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2 years ago

The individuality of an organism is determined

Biology

2 answers:

guajiro [1.7K]2 years ago

5 0

1 sequence of bases in DNA

Crazy boy [7]2 years ago

4 0

Answer:

(1)sequence of bases in DNA

Explanation:

Because it from there codons are obtained to then form amino acids to then make protein, which are like building blocks in a person

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the chemicals in cigarette smokers are known to cause cancer propose a series of steps that could lead to the development of lun

Aleks [24]

Answer:

Cell deterioration

Explanation:

Once the cells first come in contact, they immediately create a cell shield that is composed of weaker cells, while the rest continue their work, the problem with this, is that their is a lack of cells to do work and the weaker cells are slowly dying and creating holes for the harmful chemicals to enter, as the cells deteriorate they clot together and create a lump in a final attempt, and it ends up creating deadly weight in the lungs.

4 0

3 years ago

Which of these has not been used as an RNA probe?

Serhud [2]

Answer:

I think the answer is Cellular Probes.

Explanation:

I hope this helps! Correct me if I am wrong.

4 0

2 years ago

What is a control group in biology ?

Irina-Kira [14]

The group that doesn't receive treatment/medicine.

8 0

4 years ago

Organisms with the genotypes aabbccdd and aabbccdd are crossed. What are the expected proportions of the following progeny?

Dvinal [7]

Answer:

a) $\frac{27}{64}$

b) $\frac{1}{32}$

c) $\frac{27}{64}$

d) $\frac{3}{64}$

Explanation:

The correct question is

Organisms with the genotypes AABbCcDd and AaBbCcDd are crossed. What are the expected proportions of the following progeny?

a. A_B_C_D_

b. AabbCcDd

c. a phenotype identical to either parent

d. A_B_ccdd

Solution

In such question the probability for each allele pair is to be determines separately

For instance,

AA * Aa will produce AA, Aa, AA, Aa this means that all the the probability of getting both AA and Aa is $\frac{1}{2}$

Like wise when Bb and Bb are crossed, BB, Bb, Bb, and bb are produced. So the probability of getting dominant trait i.e BB or Bb is $\frac{3}{4}$ and recessive trait i.e bb is $\frac{1}{4}$

Chance to get homozygous bb only or BB only is $\frac{1}{4}$

and chance of getting Bb is $\frac{1}{2}$

Like Bb and Bb cross, the same will be the probabilities for Cc and Cc cross and Dd and Dd cross

Part A)

$\frac{1}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{27}{64}$

Part B)

$\frac{1}{4} * \frac{1}{2} * \frac{1}{2}* \frac{1}{2}\\= \frac{1}{32}$

Part C)

$\frac{1}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{27}{64}$

Part D)

$\frac{3}{4} * \frac{1}{4} * \frac{1}{4} * \frac{1}{4} \\= \frac{3}{64}$

5 0

3 years ago

If an mRNA strand is 6399 nucleotides long how many amino acids are coded for ( Numeric answer)

sergey [27]

Answer:

If an mRNA strand is 6399 nucleotides long, it will code for 2132 amino acids, as the last triplet is the terminating codon.

Explanation:

Codons are found in the RNA chain and are made up of nucleotides trios, whose specific sequence determines the genetic code.

There are 4 nitrogenous bases in RNA - Adenine, Guanine, Cytosine and Uracil - which when combined in trios give rise to 64 possible codon combinations that code for 20 amino acids, so an amino acid can be formed by more than one codon.

Determining how many amino acids are encoded according to the amount of nucleotides in the mRNA would be as easy as <u>dividing the number of nucleotids in the chain by 3</u>, but considering that the last codon is not taken into account, since it is the termination codon.

Amino acids = (amount of nitrogenous bases in mRNA / 3) - 1
Amino acids = (6399 / 3) - 1
Amino acids = 2133 - 1 = 2132

3 0

3 years ago