No, there is not a product rule for integration.
To integrate (2x - 1)(6x + 5), start expanding the product:
(2x - 1)(6x + 5) = 12x^2 + 10x - 6x - 5 = 12x^2 + 4x - 5.
Now, I guess you know how to integrate that:
∫ (12x^2 + 4x - 5) dx = ∫12x^2 dx + ∫4x dx + ∫ (-5) dx = 4x^3 + 2x^2 - 5x + C
Answer: i think the answer is 17 x-10y=0
Answer:
Step-by-step explanation:
Assuming that for each option, you play the same number of games,x
Let y represent the cost of playing x games using option A
Option A is to buy a membership card and pay $2 every time you go to the gym. The membership card costs $20. It means that
y = 20 + 2x
Let z represent the cost of playing x games using option B
Option B is to pay $4 each time you go. It means that
z = 4x
To determine how many games will be played before cost of option A equal to the cost of option B, we would equate y to z. It becomes
20 + 2x = 4x
4x - 2x = 20
2x = 20
x = 20/2 = 10
It will take 10 games for both to be the same
<span>Equation F can be written as 2d + 1 = 3d + 7.</span>
Answer:
5
Step-by-step explanation:
<u>Steps of calculation:</u>
- 7 + 1 - 18 : 6 =
- 7 + 1 - 3 =
- 8 - 3 =
- 5
Answer is 5
