Which one is big between these numbers:
2 answers:
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Answer:
37.27% probability that he or she will have a heart attack.
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Periodontal disease
Event B: Heart attack
Researchers discovered that 82% of people who have suffered a heart attack had periodontal disease, an inflammation of the gums.
This means that
Only 33% of healthy people have this disease.
This means that
Suppose that in a certain community heart attacks are quite rare, occurring with only 15% probability.
This means that
If someone has periodontal disease, what is the probability that he or she will have a heart attack
37.27% probability that he or she will have a heart attack.
Answer:
Step-by-step explanation:
arithmetic sequence formula:
where is the first term and
is the common difference
Given:
⇒
⇒
Given:
⇒
⇒
Rearrange the first equation to make the subject:
a = 32 - 9d
Now substitute into the second equation and solve for
(32 - 9d) + 11d = 106
⇒ 32 + 2d = 106
⇒ 2d = 106 - 32 = 74
⇒ d = 74 ÷ 2 = 37
Substitute found value of into the first equation and solve for
:
a + (9 x 37) = 32
a + 333 = 32
a = 32 - 333 = -301
Therefore, the equation is: