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stealth61 [152]
2 years ago
13

Match each of the terms listed on the left with exactly one best description from the column on the right geometry

Mathematics
1 answer:
Rzqust [24]2 years ago
4 0

what do we have in the next year for a pet sitter to take a look on this is one thing we would love if there are a lot to offer you can make a difference for the world to make your business easier for 170m to make your business a perfect life to keep stealing

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What is the common ratio for this sequence? Hurry!!!!!
valina [46]
A common ratio for that sequence is r = 5/1
6 0
2 years ago
Read 2 more answers
Factor the polynomial. x2 - 5xy + 6y2 A) (x - 3)(x - 2) B) (x - 6y)(x + y) C) (x - 3y)(x - 2y) D) (x + 3y)(x + 3y)
Elden [556K]
X^2 - 5xy + 6y^2 = <span>(x - 3y)(x - 2y) 

answer is </span><span>C) (x - 3y)(x - 2y)

hope that helps</span>
8 0
2 years ago
A rectangle has an area of 96 cm2 The length of the rectangle is 4 cm longer than the width. Work out the length and width of th
Svetach [21]
Area of a rectangle: 2(L+W)
length: 4+W

Area: 2(4+W) + 2W = 96
8+2W+2W = 96
8+4W = 96
4W = 88
W= 22cm

Calculate for length: 2L + 2(22) = 96
2L + 44 = 96
2L = 52
L = 26cm

• The length is 26cm and width is 22 cm.
3 0
3 years ago
The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt
Marizza181 [45]

Answer:

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

L=w+2

now, we can find area

A=L\times W

now, we can plug it

A=(w+2)\times w

A=w^2+2w

we are given area =6

so, we can set it equal

and then we can solve for w

w^2+2w=6

w^2+2w-6=0

we can use quadratic formula

ax^2+bx+c=0

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}

w=-1+\sqrt{7},\:w=-1-\sqrt{7}

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

7 0
3 years ago
The answer for this problem
ElenaW [278]

Only the 3. option can be used. All other values dont fit


4 0
3 years ago
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