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3 years ago

What is £300 divided into a ratio of 3:7

2 answers:

7 0

First you add the ratio together 3+7=10 Then you do £300 divided by 10 = £30
Then you do £30 X 3 (from the ratio in the beginning) which equals £90 
Then you do £30 X 7 (also from the ratio in the beginning) which equals £210 
The ratio is £90:£210 
Also you can add the ratios up so that it equals £300 the number you started with 
£90+£210=£300 
Hope I helped :)

3241004551 [841]3 years ago

5 0

A) sum 3 + 7 =10
b) divide £300 ÷ 10 = £30
c) multiply:
3 x 30 = £90
7 x 30 = £210

Values are: £90 and £210

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What is the probability of throwing a number greater than 4 when rolling a number cube that has sides labeled 1, 2, 3, 4, 5, 6?

Leona [35]

What is probability rolling a number greater than 4?

The only numbers there are is 5 and 6.
That means that there are 2 outcomes out of 6 total outcomes.
That would be 2/6.
Divide the the top and bottom by 2.
In simplest form it would be 1/3.
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The answer is 1/3. The probability of throwing a number greater than 4 is 1/3.

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2 years ago

How many different six-digit decimal numbers can be formed where the first digit is a 1 or the last digit is a 5?

Mariulka [41]

Answer:

10000 different numbers

Step-by-step explanation:

The numbers will have the form 1XXXX5, in this case, the order is important because 123465 is a different number to 123645. To know the total of differents decimal numbers, use the formula of permutation with repetition:

$n^r$

$n$ is the number of options, $n=10$ , and $r$ the number of times you have to place a digit, $r=4$ .

$10^4=10000$

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2 years ago

For how many real values of x is <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B120-%5Csqrt%7Bx%7D%7D%20" id="TexFormula1" title

leva [86]

A good place to start is to set $\sqrt{x}$ to y. That would mean we are looking for $\sqrt{120-y}$ to be an integer. Clearly, $y\leq 120$ , because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since $\sqrt{x}$ is a radical, it only outputs values from $[0,\infty]$ , which means y is on the closed interval: $[0,120]$ .

With that, we don't really have to consider y anymore, since we know the interval that $\sqrt{x}$ is on.

Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval $[0,120]$ , which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

$\sqrt{120-\sqrt{x}}=k \implies \\ \sqrt{x}=k^2-120 \implies\\ x=(k^2-120)^2$

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.

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2 years ago

Mr. Thompson had a balance of $283.12 in his checking account at the beginning of the month he wrote checks for $23.09 $7.56 $12

ryzh [129]

Account balance is $123.08

Step-by-step explanation:

Step 1: Balance in Thompson's account = $283.12. Calculate the total amount of checks Thompson wrote in the month.

Total amount of checks = $23.09 + $7.56 + $125.11 + $4.28

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Step 2: Calculate his balance.

Account balance = $283.12 - $160.04

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2 years ago

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kkurt [141]

Answer

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2 years ago