Joe borrowed $35 on Monday, then he borrowed $55 on Tuesday. On Friday he paid back $20. How much does Joe still owe?

A manufacturer of a new medication on the market for Alzheimer's disease makes a claim that the medication is effective in 65% o

NeX [460]

Answer:

$z=\frac{0.639 -0.65}{\sqrt{\frac{0.65(1-0.65)}{180}}}=-0.309$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults with the medication was effective is not significantly less than 0.65

Step-by-step explanation:

Data given and notation

n=180 represent the random sample taken

X=115 represent the adults with the medication was effective

$\hat p=\frac{115}{180}=0.639$ estimated proportion of adults with the medication was effective

$p_o=0.65$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is less than 0.65.:

Null hypothesis: $p \geq 0.65$

Alternative hypothesis: $p < 0.65$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.639 -0.65}{\sqrt{\frac{0.65(1-0.65)}{180}}}=-0.309$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults with the medication was effective is not significantly less than 0.65

3 0

3 years ago

8 ( j - 4 ) = 2(4j - 16 )

Tanya [424]

8j-32=8j-32
J=j
Js value is infinite

7 0

3 years ago

Read 2 more answers

The ratio of the radii of two circles is 2:3. The diameter of the smaller circle is 15 mm. What is the length of the diameter of

mixer [17]

The answer is 11.25 mm.

A diameter of a circle is twice of its radius: d = 2r ⇒ r = d/2

small circle large circle
radius: r1 radius: r2 = ?
diameter: d1 = 15 mm
⇒ r1 = d1/2 = 15/2 mm

Since the ratio of the radii of two circles is 2:3, we have:
r1 : r2 = 2 : 3
which can also be expressed as:
 $\frac{r1}{r2}= \frac{2}{3}$

We know that r1 is 7.5, so let's implement it:
 $\frac{7.5}{r2} = \frac{2}{3}$

Let's multiply both sides of the by 3r2:
$3r2* \frac{7.5}{r2} =3r2* \frac{2}{3}$
⇒ $3 * 7.5 = 2*r2$
$22.5 = 2*r2$
⇒ $r2= \frac{22.5}{2} =11.25 mm$

5 0

3 years ago

Read 2 more answers

4444444444444444444444444444444444444444444444444444444444

Liula [17]

If you want to solve that put it in the formula to find the slope
M=
Y1-y2
---------
X1-x2

And plug that into slope int form with one of the points to find the y int/ b value and then your have ur equ

4 0

3 years ago

While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between

aleksandr82 [10.1K]

Answer:

The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

Step-by-step explanation:

Let the random variable X denote the water depths.

As the variable water depths is continuous variable, the random variable X follows a continuous Uniform distribution with parameters a = 2.00 m and b = 7.00 m.

The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

$P(2.25$

$=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55$

Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.

6 0

3 years ago