Answer:
C
Step-by-step explanation:
Given
+ ![\left[\begin{array}{ccc}3&1\\-1&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%5C%5C-1%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Add corresponding elements to obtain the sum, that is
= ![\left[\begin{array}{ccc}-2+3&3+1\\2-1&4+2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%2B3%263%2B1%5C%5C2-1%264%2B2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
→ C
The first missing number is 4
The second missing number is 1.6
Step-by-step explanation:
Solution,
since two of these triangle are similar so,
i) LK/LJ=MN/NO
or,j/8=18/12
or,j=18×8/12
.°. j = 12m
ii)JK/JL=MO/NO
or,10/8=n/12
or,120/8=n
.°.n=15m
Change each of the fractions into decimals.
1/8 becomes 0.125
-1/7 becomes -0.143
and -0.02555
0.2
In order from least to greatest,
-0.143, -0.02555, 0.125, 0.2
OR
-1/7, -0.02555, 1/8 and 0.2