Answer:
Each one has two fatty acid chains and the glycerol backbone is bonded to a small polar group.
Explanation:
Phospholipid is a unique form of lipid. The bonding of the glycerol backbone to the polar phosphate group makes phospholipid to have dual solubility unlike general triglycerides.
The polar head is said to be hydrophillic that is <u>water loving,</u> while the two carbon chains that retained lipid features are hydrophobic <u>water hating.</u>
Therefore if a phopholipid is placed in water, in relation to its functions as component of cell membrane, it forms a bi-layer in which the water loving portion hydrophilic head points into the surrounding watery medium, while the hydrophobic layer points inwards far away from the watery medium into the internal cellular layer to form an impermeable barrier to hydrophilic (polar) substances.
This forms the basis of the phospholipd bilayer of the cell membrane. And it controls the permeability of the cell membrane to influx substances into the cells.
Answer:
The contrast in coloration was pivotal to determine if predators attack snakes based on their colors.
It was for studying MIMICRY in snakes.
Assuming all the.snakes were the same the number of attacks will not indicate anything about the effect of the colored rings.
This question on the need for provision of a controlled experiment during experimental investigation. Thus in order to test the effect of a particular condition,another contrasting condition must be provided to determine if the condition under investigation is the actual results obtaned or the influence of other factors in the environment or in the experiment.
The change in the color of the ring is the VARIABLE .In the artificial snake the variable is the presence of this coloed rings against its absence in this snake.
since it changes in the artificial snake
Explanation:
9514 1404 393
Answer:
- time: 1.122 seconds
- range: 10.693 m
- maximum height: 1.543 m
Explanation:
<u>Given</u>:
runner is launched at 30° angle to horizontal at 11 m/s
acceleration due to gravity is g = -9.8 m/s²
<u>Find</u>:
runner's hang time
runner's distance to the landing point
runner's maximum height
<u>Solution</u>:
The (horizontal, vertical) speed components will be ...
(11 m/s)(cos(30°), sin(30°)) = (5.5√3 m/s, 5.5 m/s)
The time of flight can be found from the height formula:
h(t) = 1/2gt² +vt . . . . . . where v is the vertical speed at launch
The time we're concerned with is the time when h(t)=0 and t>0.
0 = -4.9t^2 +5.5√3t = t(-4.9t +5.5√3)
The second factor is zero when ...
t = (5.5√3)/4.9 ≈ 1.122 . . . seconds hang time
__
The distance to the landing point will be the product of horizontal speed and hang time:
d = (5.5 m/s)(5.5√3/4.9 s) ≈ 10.693 m . . . . distance to landing
__
The maximum height can be found from the formula (based on conversion of kinetic energy to potential energy) ...
h = v²/|2g| = (5.5 m/s)²/(2(9.8 m/s²)) ≈ 1.543 m . . . . maximum height
I believe that would be small polar and nonpolar molecules.
Hope it helps!
A microscope hope i helped
