Using the given formula, the density of the material is 2.015 g/mL
<h3>Calculating Density </h3>
From the question, we are to determine the density of the material
From the given formula
Density = Mass / Volume
And from the given information,
Mass = 65.5 g
and volume = 32.5 mL
Putting the parameters into the equation,
Density = 65.5/32.5
Density = 2.015 g/mL
Hence, the density of the material is 2.015 g/mL.
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The volume of base required to completely neutralize the acid is 3.2 mL of NaOH.
The equation of the reaction is;
2NaOH(aq) + H2SO4(aq) -----> Na2SO4(aq) + 2H2O(l)
From the question;
Concentration of acid CA = 0.426M
Concentration of base CB = 2.658M
Volume of acid VA = 10.00mL
Volume of base VB = ?
Number of moles of acid NA = 1
Number of moles of base NB = 2
Using the relation;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
VB = CAVANB/CBNA
VB = 0.426M × 10.00mL × 2/ 2.658M × 1
VB = 3.2 mL
Learn more: brainly.com/question/6111443
Answer:flashover
Explanation: flashover are event that occurs when all of the combustible materials in a room reach their ignition temperatures at the same time
Answer:
4 moles of Na are needed.
Answer:
8306.76
Explanation:
you just calcuate 8.12 x 1023 and that will give you the answer
<h2>
PLZ mark me as a BRAINLIEST</h2>