<u>Answer:</u> The equilibrium constant for the total reaction is 
<u>Explanation:</u>
We are given:
We are given two intermediate equations:
<u>Equation 1:</u> 
The expression of 
for the above equation is:
![K_{c_1}=\frac{[NH_3]^2}{[N_2][H_2]^3}](https://tex.z-dn.net/?f=K_%7Bc_1%7D%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D)
![0.282=\frac{[NH_3]^2}{[N_2][H_2]^3}](https://tex.z-dn.net/?f=0.282%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D)
.......(1)
<u>Equation 2:</u> 
The expression of 
for the above equation is:
![K_{c_2}=\frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=K_%7Bc_2%7D%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
![41=\frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=41%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
......(2)
Cubing both the sides of equation 2, because we need 3 moles of HI in the main expression if equilibrium constant.
![(41)^3=\frac{[HI]^6}{[H_2]^3[I_2]^3}](https://tex.z-dn.net/?f=%2841%29%5E3%3D%5Cfrac%7B%5BHI%5D%5E6%7D%7B%5BH_2%5D%5E3%5BI_2%5D%5E3%7D)
Now, dividing expression 1 by expression 2, we get:
![\frac{K_{c_1}}{K_{c_2}}=\left(\frac{\frac{[NH_3]^2}{[N_2][H_2]^3}}{\frac{[HI]^6}{[H_2]^3[l_2]^3}}\right)\\\\\\\frac{0.282}{68921}=\frac{[NH_3]^2[I_2]^3}{[N_2][HI]^6}](https://tex.z-dn.net/?f=%5Cfrac%7BK_%7Bc_1%7D%7D%7BK_%7Bc_2%7D%7D%3D%5Cleft%28%5Cfrac%7B%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D%7D%7B%5Cfrac%7B%5BHI%5D%5E6%7D%7B%5BH_2%5D%5E3%5Bl_2%5D%5E3%7D%7D%5Cright%29%5C%5C%5C%5C%5C%5C%5Cfrac%7B0.282%7D%7B68921%7D%3D%5Cfrac%7B%5BNH_3%5D%5E2%5BI_2%5D%5E3%7D%7B%5BN_2%5D%5BHI%5D%5E6%7D)
![\frac{[NH_3]^2[I_2]^3}{[N_2][HI]^6}=4.09\times 10^{-6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNH_3%5D%5E2%5BI_2%5D%5E3%7D%7B%5BN_2%5D%5BHI%5D%5E6%7D%3D4.09%5Ctimes%2010%5E%7B-6%7D)
The above expression is the expression for equilibrium constant of the total equation, which is:
Hence, the equilibrium constant for the total reaction is
it is 12.51 grams cause u just add them together
The balanced equation
6CO₂ + 6H₂O = C₆H₁₂O₁₆ + O₂
<h3>Further explanation</h3>
Given
Reaction
CO2 + _H2O = _C6H12O16 + _O2
Required
Balanced equation
Solution
Give a coefficient
aCO₂ + bH₂O = C₆H₁₂O₁₆ + cO₂
Make an equation
C, left = a, right = 6⇒a=6
H, left = 2b, right = 12⇒2b=12⇒b=6
O, left=2a+b, right = 16+2c⇒2a+b=16+2c⇒2.6+6=16+2c⇒2c=2⇒c=1
The equation becomes :
<em>6CO₂ + 6H₂O = C₆H₁₂O₁₆ + O₂</em>
Answer:
I dont get what you need help with
Explanation:
Answer:
Explanation:
The quantity of atoms within the mass of copper is determined by multiplying the quantity of moles by the Avogadro's Number:
