Answer:
M.Mass = 120 g/mol
Explanation:
Data Given:
Volume = V = 0.0650 L
Temperature = T = 547 °C = 820.15 K
Pressure = P = 70.5 kPa = 0.695 atm
Gas Constant = R = 0.082057 L.atm.mol⁻¹.K⁻¹
Formula Used:
Assuming that the gas is ideally then according to ideal gas equation,
P V = n R T
Solving for n,
n = P V / R T
Putting Values,
n = (0.695 atm × 0.0650 L) ÷ (0.082057 L.atm.mol⁻¹.K⁻¹ × 820.15 K)
n = 6.71 × 10⁻⁴ moles
Now, Knowing that,
Moles = Mass / M.Mass
Or,
M.Mass = Mass / Moles
Putting values,
M.Mass = 8.06 × 10⁻² g / 6.71 × 10⁻⁴ mol
M.Mass = 120 g/mol
C because the heart and lungs are involved with gases
Answer:
D). Much lower than
Explanation:
When a ketone and its enol are in equilibrium, under most conditions the concentration of the enol is <u>Much lower than</u> the concentration of the ketone
because :
Carbon- oxygen bond is more stable(stronger) than Carbon-Carbon Bond
Keto - enol tautomerism is :
Ketone has C=O and enol has C=C
C=O bond energy is 745 kJ/mol
C=C bond energy is 614 kJ/mol
Volume of the metal = change in volume reading
Volume = 37.4 - 33
Volume = 4.4 ml
Density = mass / volume
Density = 7.101 / 4.4
Density = 1.61 g/ml
Answer:
The volume of basketball is 7216.5 cm³.
Explanation:
Given data:
Radius of ball = 12 cm
Volume of ball = ?
Solution:
We will apply the volume formula of sphere.
V = 4/3 ×π×r³
we know that,
π = 22/7
r = 12 cm
Now we will put the values in formula.
V = 4/3 × 3.14 × (12 cm)³
V = 4/3 × 3.14 ×1728 cm³
V = 7216.5 cm³
Thus, the volume of basketball is 7216.5 cm³.
