Measuring density is very important for many different industries because the density measurement will help determine the characteristics of a material, for example, whether the material will float or sink. Knowing the density of a material helps in determining the mass and volume of a material, all of which are extremely important measurements in all industries.
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Related questions (More answers below)
Answer:
2.122×10^25atoms
Explanation:
number of moles=mass/molar mass
7.05moles= mass of pyridine/79
reacting mass of pyridine=556.95
C5H5N= (12×5)+(5)+(14)=79
C5=60
to find the mass of carbon in 556.95g of pyridine we take the stoichometric ratio
60[C5] -----> 79[C5H5N]
x[C5] --------> 556.95g[C5H5N]
cross multiply
x=(60×556.95)/79
x=423g of carbon
moles=mass/molar mass
moles of carbon=423/12
moles=35.25moles of carbon
moles=number of particles/Avogadro's constant
35.25=number of particles/6.02×10^23
number of particles=2.122×10^25atoms of carbon
Heat
gained in a system can be calculated by multiplying the given mass to the
specific heat capacity of the substance and the temperature difference. It is
expressed as follows:<span>
Heat = mC(T2-T1)
When two objects are in contact,
it should be that the heat lost is equal to what is gained by the other. From
this, we can calculate things. We do as follows:
<span>Heat gained =
Heat lost</span>
mC(T2-T1) = - mC(T2-T1)
C(liquid water) = 4.18 J/gC
C(ice) = 2.11 J/gC
</span><span>(354 mL)(1.0 g/mL)(4.18 J/gC)(26 C - 6 C) = m(2.11 J/gC)(6 - 0C) </span><span>
m = 2337.63 g of ice
</span>
From the calculation, the molar mass of the solution is 141 g/mol.
<h3>What is the molar mass?</h3>
We know that;
ΔT = K m i
K = the freezing constant
m = molality of the solution
i = the Van't Hoft factor
The molality of the solution is obtained from;
m = ΔT/K i
m = 3.89/5.12 * 1
m = 0.76 m
Now;
0.76 = 26.7 /MM/0.250
0.76 = 26.7 /0.250MM
0.76 * 0.250MM = 26.7
MM= 26.7/0.76 * 0.250
MM = 141 g/mol
Learn more about molar mass:brainly.com/question/12127540?
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Cambium - <span>a cellular plant tissue from which phloem, xylem, or cork grows by division, resulting (in woody plants) in secondary thickening.</span>
