(2) Adding more O2(g) would shift the equilibrium to the right because a higher concentration of oxygen is offered than its initial position, therefore more products have to be yielded to maintain equilibrium.
<em>Calculate the molar fraction of NaClO in a commercial bleach solution that contains 3.62% by mass of NaClO in water</em>
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<h3>Further explanation</h3>
convert mass to mol
mol NaClO (MW=74.5 g/mol) :
mol H₂O (MW= 18 g/mol) :
Total mol :
0.0486 + 5.354 = 5.4026
mol fraction of NaClO :
The answer is hydrobromic acid.
That is the name for aqueous HBr is hydrobromic acid.
If there is no water that is if it is not aqueous then the name will be hydrogen bromide but as it is acid and in aqueous state so the name will be hydrobromic acid. As it is acid that's why the suffic ic is used and as it is in aqueous state, so hydro is used.
Answer: D. Processing
Explanation: 100% on topic test also its in my e notes.
Answer:
Percentage mass of copper in the sample = 32%
Explanation:
Equation of the reaction producing Cu(NO₃) is given below:
Cu(s)+ 4HNO₃(aq) ---> Cu(NO₃)(aq) + 2NO₂(g) + 2H₂O(l)
From the equation of reaction, 1 mole of Cu(NO₃) is produced from 1 mole of copper. Therefore, 0.010 moles of Cu(NO₃) will be produced from 0.010 mole of copper.
Molar mass of copper = 64 g/mol
mass of copper = number of moles * molar mass
mass of copper = 0.01 mol * 64 g/mol = 0.64 g
Percentage by mass of copper in the 2.00 g sample = (0.64/2.00) * 100%
Percentage mass of copper in the sample = 32%
