1 kg/L -------------- 0.001 kg/mL
22.4 kg/L --------- ??
22.4 x 0.001 / 1 => 0.0224 kg/mL
<u>Answer:</u> The mass of gallium produced by the electrolysis is 0.0354 grams.
<u>Explanation:</u>
The equation for the deposition of Ga(s) from Ga(III) solution follows:

- To calculate the total charge, we use the equation:

where,
C = charge
I = current = 0.490 A
t = time required (in seconds) =
(Conversion factor: 1 min = 60 s)
Putting values in above equation, we get:

- To calculate the moles of electrons, we use the equation:

where,
C = charge = 147 C
F = Faradays constant = 96500

- Now, to calculate the moles of gallium, we use the equation:

where,
n = number of electrons transferred = 3
Putting values in above equation, we get:

- To calculate the mass of gallium, we use the equation:

Moles of Gallium = 
Molar mass of Gallium = 69.72 g/mol
Putting values in above equation, we get:

Hence, the mass of gallium produced by the electrolysis is 0.0354 grams.
Assuming there is excess acid, the equation for the reaction is Zn + 2HCl -> ZnCl2 + H2.
Mols of zinc = 20/65 (mass/relative atomic mass)
Ratio of Zn : ZnCl2 = 1 : 1
Hence mols of Zinc = mols of Zinc chloride
Mass of ZnCl2 = (20/65)(65+71)
= 41.8g
Answer:
Kelvin = Celsius + 273.15
Explanation:
Instead of 273.15 you can use just 273 as well