Question

I really need help asap!!

Answer 1

Given:

A figure of a parallelogram.

The vertex angles are $(12b+8)^\circ,(5b+2)^\circ,2a^\circ$.

To find:

The values of a and b.

Solution:

We know that the pairs of consecutive angles of a parallelogram are supplementary angles. It mean their sum is 180 degrees.

$(12b+8)^\circ+(5b+2)^\circ=180^\circ$       (Supplementary angles)

$(17b+10)^\circ=180^\circ$

$17b+10=180$

Subtract 10 from both sides.

$17b=180-10$

$17b=170$

Divide both sides by 17.

$b=\dfrac{170}{17}$

$b=10$

Now,

$(5b+2)^\circ=(5(10)+2)^\circ$

$(5b+2)^\circ=(50+2)^\circ$

$(5b+2)^\circ=52^\circ$

And,

$(5b+2)^\circ+2a^\circ=180^\circ$       (Supplementary angles)

$52^\circ+2a^\circ=180^\circ$

$2a^\circ=180^\circ-52^\circ$

$2a^\circ=128^\circ$

Divide both sides by 2.

$a^\circ=\dfrac{128^\circ}{2}$

$a^\circ=64^\circ$

$a=64$

Therefore, the value of a is 64 and the value of b is 10.