I’m not sure but since no one else commented I would think it’s D, I think you take the first number like 6 for a and subtract the first number for b like 3
U={1,2,3,4,5,6,7,8,9} <br>
a={2,4,6,8} <br>
b={3,6,9} <br><br>
What is the set AUB?
ella [17]
Answer:
AUB = {2,3,4,6,8,9}
Step-by-step explanation:
The set u should not be included in set AUB
Factor:
3x^2 + 27
= 3(x^2 + 9)
Answer is 3(x^2 + 9), when factored.
A) (3x + 9i)(x + 3i)
= (3x + 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + (9i)(x) + (9i)(3i)
= 3x^2 + 9ix + 9ix + 27i^2
= 27i^2 + 18ix + 3x^2
B) (3x - 9i)(x + 3i)
= (3x + - 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + ( - 9i)(x) + (- 9i)(3i)
= 3x^2 + 9ix - 9ix - 27i^2
= 27i^2 + 3x^2
C) (3x - 6i)(x + 21i)
= (3x + - 6i)(x + 21i)
= (3x)(x) + (3x)(21i) + (- 6i)(x) + ( -6i)(21i)
= 3x^2 + 63ix - 6ix - 126i^2
= - 126i^2 + 57ix + 3x^2
D) (3x - 9i)(x - 3i)
= (3x + - 9)(x + - 3)
= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
= 3x^2 - 9ix - 9x + 27i
= 9ix + 3x^2 + 27i - 9x
Hope that helps!!!
Answer: sure
Step-by-step explanation:
Answer:
The number is 5
Step-by-step explanation:
Let x represent the number
Now let's break it down!
Sum of a number and 3 gives;
x + 3
This is then doubled to give;
2* (x + 3)
This is added to the product of 6 and the original number to give 46
Product of 6 and the original number = 6 * x
Now 2* (x + 3) is added to 6 * x to give 46
2* (x + 3) + 6*x = 46
2x + 6 + 6x = 46
8x + 6 = 46
Subtract 6 from both sides
8x + 6 - 6 = 46 - 6
8x = 40
x = 40/8
x = 5
Hence, the number is 5
