The answer for that question is 1 3/5
No
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Answer:
The ball will go to maximum height of 56.25 meters.
Step-by-step explanation:
It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec
Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :

h = 0
..............(1)
We need to find the maximum height reached by the ball. For maximum height,


t = 1.875 seconds
Put the values of t in equation (1). So,

h(t) = 56.25 meters
So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.
We are given with
p2 + 2pq = 0.64
and another formula is
p2 + 2pq + q2 = 1
Substituting
0.64 + q2 = 1
q2 = 1 - 0.64
q2 = 0.36
q = 0.6
Another formula is
p + q = 1
p = 1 - 0.6
p = 0.4
What is asked is 2pq
p2 + 2pq = 0.64
2pq = 0.64 - 0.4^2
2pq = 0.48
There is 48% that has the heterozygous trait.
Answer:
4. 87.96 yd
5. 47.12 ft
6. 34.56 cm
Step-by-step explanation:
4. diameter(d) = 28 yd,
perimeter = πd = 87.96 yd (rounded to 2 dp)
5. radius(r) = 7.5 ft
perimeter = 2πr = 47.12 ft (rounded to 2 dp)
6. diameter (d) = 11 cm
perimeter = πd = 34.56 cm
Answered by GAUTHMATH