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TiliK225 [7]
3 years ago
13

Brad's family traveled

Mathematics
2 answers:
postnew [5]3 years ago
4 0

Answer : 4/7

Here it's given that Brad's family travelled 2/7 of the total distance to his uncle's house on Saturday . So if we assume the total distance to be 1 , then the remaining distance will be ,

\sf\longrightarrow 1 - \dfrac{2}{7}=\dfrac{7-2}{7}=\boxed{\dfrac{5}{7}}

Again it's given that they travelled 4/5 of the remaining distance on Sunday . So , the distance travelled would be ,

\sf\longrightarrow \dfrac{4}{5}\times \dfrac{5}{7}=\boxed{\sf \dfrac{4}{7}}

Therefore Brad's family travelled 4/7 of the total distance on Sunday .

Zigmanuir [339]3 years ago
4 0

Distance travelled by them on Saturday = 2/7

Distance travelled by them on Sunday = 4/5

Let total distance be 1, So according to that

\sf1 -  \frac{2}{7}

\sf \frac{7 - 2}{7}

\sf \frac{5}{7}

Now, Multiply the distance travelled by them on Saturday by the fraction of distance they travelled on Sunday.

\sf \frac{\cancel5}{7}  \times  \frac{4}{\cancel5}

\sf \frac{1}{7}  \times  \frac{4}{1}

\sf \frac{4}{7}

<em>Thus, Brad's family travelled 4/7 of the distance on Sunday...~</em>

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