y = 6x - 4
Substitute the given x values to solve for y.
x = 1:
y = 6(1) - 4
y = 6 - 4
y = 2
1 = 2
x = 3:
y = 6(3) - 4
y = 18 - 4
y = 14
3 = 14
x = 10:
y = 6(10) - 4
y = 60 - 4
y = 56
10 = 56
x y
1 2
3 14
10 56
3x²+x-5=0
a = 3, b = 1, c= -5
-> ∆ ( delta ) = b²-4ac = 61 > 0
-> x1 =( -b+√∆ )÷ 2a =...
x2 = (-b-√∆)÷2a =...
p/s: do your teachers teach you how to use ∆ ( delta ) in maths calculation ? i live in europe and our teachers teach us that way. however, it is a rịght and fast way. you should learn it.
Answer:
Alexander is incorrect because the expressions are not equivalent.
Step-by-step explanation:
If the expression is evaluated for any value of x, y; the result will not be same.
For instance, let assume x = 1 and y = 2
3x + 4y = 3 + 4 = 7
(3)(4) + xy = (3)(4) + (1 * 2) = 12 + 2 = 14
So, the expressions are not the same and Alexander is incorrect.
Answer:
a y=3/2× Pls help me do me one
a
4 1/3
Hope this helped :)
The explanation:
3 goes into 13 4 times. So 4 is your whole number.
You have 1 number left over so that is your numerator.
Your denominator does not change.
You can not simplify any more. <span />
