Let
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so

where
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

where
denotes the CDF of
, and
denotes the inverse CDF. We have

Similarly, because 20% of students obtain less than 40 marks, we have

so that

Then
are such that


and we find

2 committees. 6 is divisible by 3 twice, 8 is divisible by 4 twice.
Answer:
1 + and a half = 1 in a half
Step-by-step explanation:
The numerator in the first fraction is closest to
10, so the fraction is nearest to 1.
The numerator in the second fraction is closest to 3, so the fraction is nearest to one-half.
The value of the expression can be estimated as 1 + one-half = 1 and one-half.
Answer:
Step-by-step explanation:
What did you include in your response? Check all that apply.
There would be an open circle at (2, 1). <u>Yes</u>
There would be a closed circle at (2, 3). <u>Yes</u>
There would be an open circle at (4, 3). <u>Yes</u>
There would be a closed circle at (4, −4). <u>Yes</u>
Endpoints that are not included in the domain of a particular piece of a function are represented by an open circle. <u>Yes</u>