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Mrac [35]
2 years ago
10

A water main for a street is being laid using mechanical joint pipe. the pipe comes in 18-foot and 20-foot sections, and a desig

ner determines that the water main would require 14 fewer sections of 20-foot pipe than if 18-foot sections were used. find the total length of the water main.
Mathematics
2 answers:
kipiarov [429]2 years ago
7 0

Let

x--------> the total length of the water main


we know that

the number of 20 ft pipes is x/20

and

the number of 18 ft pipes is x/18

Since they differ by 14 pipes,

we have the equation

x/18 - x/20 = 14

Solve for x (by canceling fractions)

20x - 18x = 14*18*20

x = (14*18*20)/2

x = 2,520 ft


therefore


the answer is

the total length of the water main is 2,520 ft

zimovet [89]2 years ago
5 0

To solve this problem you must apply the proccedure shown below:

1. You can write the following expression, where the variable x is the total length of the water main:

\frac{x}{18}-\frac{x}{20}=14

2. Now, solve for x, as following:

\frac{10x-9x}{180}=14\\ x=(14)(180)\\ x=2520

Therefore, the answer is: 2520 feet

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Answer:

Step-by-step explanation:

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3 years ago
Adult tickets to a a basketball game cost $5. Student tickets cost $1. A total of $2,757 was collected on the sale of 1,185 tick
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Answer:

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Number Of Students Tickets=792

Step-by-step explanation:

Let 'x' be the Adult's tickets

Let 'y' be the Student's tickets

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5x+y=2757(total cost of tickets)

-(5x+y=2757)x+y=1185

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x= (-1572)÷-4

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