Answer:
2). As x-> -∞, f(x)->∞
As x-> ∞, f(x)-> -∞
5). As x-> -∞, f(x)-> -∞
As x-> ∞, f(x)-> ∞
3). As x-> -∞, f(x)-> -∞
As x-> ∞, f(x)-> ∞
6). As x-> -∞, f(x)-> ∞
As x-> ∞, f(x)-> ∞
Step-by-step explanation:
I just watched a quick video so you can't completely trust me, but i tried my best. Hopefully someone more trustworthy for this comes in.
Answ(0,2)
By putting x 0 and y 2
Step-by-step explanation:
You know 1 is not a root because the sum of the coeffcients of the equation is 14, not zero.
It is fairly easy to try 3 by synthetic division (see attachment), which tells you that 3 is a root and the remaining quadratic factor is x²-3x-5. The quadratic formula tells you the roots of that factor are
... x = (-b±√(b²-4ac))/(2a) = (3±√29)/2
The appropriate choices are
... C. (3-√29)/2
... D. (3+√29)/2
... F. 3
_____
The quadratic formula tells you the solution to
... ax²+bx+c=0
is x = (-b±√(b²-4ac))/(2a)
We have a=1, b=-3, c=-5.
Answer:
when its to the left
Step-by-step explanation:
A Cube, has all equal sides, namely, the length, width and height
are all equal to each other
so.. notice the picture added here
you have really, 6 squares, stacked up to each other at the edges
so...what is the Area of one of those squares?
well, if the sides are equal, let's say the side is "x" long, then
the Area is

well, you have 6 of those squares, thus

solve for "x", to get one side's length