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Romashka-Z-Leto [24]
4 years ago
8

What is the area of this composite figure?A. 135 cm2B. 207 cm2C. 249 cm2D. 279 cm2

Mathematics
1 answer:
mariarad [96]4 years ago
7 0

Answer:

249 cm^2

Step-by-step explanation:

This problem becomes easier if we subdivide the figure, find the areas of the resulting figures and then sum them up.

Draw a vertical line straight down from the edge marked "4 cm" towards the edge marked "18 cm."  The resulting rectangle on the left is 15.5 cm long and (18 - 7.5) cm wide, or 15.5 by 10.5 cm.  Its area is 162.75 cm^2.

Next, find the area of the rectangle on the right of the line we drew.  Its width is 7.5 cm and its height (15.5 - 4) cm, resulting in an area of 86.25 cm^2.

Last, add together these two subareas:  combine 86.25 cm^2 and 162.75 cm^2.  The total area of the composite figure is then 249 cm^2 (answer).

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serg [7]
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7.5 is <span>102% </span>of 7.38

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6 0
3 years ago
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vitfil [10]
There is no solution to this equation

X≠0

The answer would be 3=6 which is an invalid answer therefor an equation with no solution.

-5x+10x+3=5x+6

Combine like terms first

5x+3=5x+6

After this whether you make it 10x=9 that’s still an invalid answer but if you subtracted 5x on both sides it’d be 3=6

Therefore x≠0
7 0
4 years ago
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Art [367]

Answer:

7x + 32 and 123

Step-by-step explanation:

One way to divide is to use the divisor as a factor in the numerator

Consider the numerator

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8 0
4 years ago
How many 3-letter sequences can be formed if the second letter must be a vowel (A, E, I, O, or U), and the third letter must be
erica [24]

Answer:

120 ways

Step-by-step explanation:

Given that, 3-letter sequences should be formed, where the second letter must be a vowel (A, E, I, O, U) and the third letter must differ from the first letter.

There are 26 alphabets in English,

so, firstly let us fix the second letter to be one of the vowels

now we are left with 25 alphabets and now let us fix the third letter to be an alphabet from the remaining 25 alphabets.

now, we are left with 24 alphabets and the first letter can be any of these 24 alphabets.

so, there are 24 ways to fill the sequence.

The same thing can be done with the other 4 vowels.

so, total number of ways =   5 × 24 = 120 ways.

 

8 0
3 years ago
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dusya [7]

Answer:

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4 years ago
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