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lesantik [10]
2 years ago
12

What is the distance between the points (-3, -1) and (1, 2)?

Mathematics
1 answer:
kiruha [24]2 years ago
4 0

Answer:  5

Step-by-step explanation:

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the 2nd one

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One more than the product of 17 and Matt's savings
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17m=2

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There are 18 female students in a class of 30, at this rate how many females are in a class off 100
OverLord2011 [107]

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7 0
3 years ago
ABDE is a rectangle ED is 8cm BDC is a right-angled triangle bc is 4.5cm ABC is a straight line the area of the rectangle abde i
Gnesinka [82]

Answer:

11.25cm^2

Step-by-step explanation:

given the area of the rectangle as 40cm^2, we can get the width of the rectangle.

Area =Length x width

40cm^2 = 8cm x width

we can divide both sides 8 to be left with the width

40/8 = 5cm

so the width is 5cm which is equal to the height of the triangle.

Area of BDC = 1/2 x base x height

BDC = 1/2 x 4.5 x 5

=11.25cm^2

5 0
3 years ago
Find the length of the shorter diagonal of a rhombus if:
Fudgin [204]

a) Area of rhombus = ½ * (diagonal1)*(diagonal 2)

Let diagonal (D2 )= longer diagonal = 15 and diagonal (D1) = shorter diagonal

90 = ½ (D1)*15

90 = 7.5 D1

Now divide both side by 7.5

90/7.5 = d1

D1= 12 units.

b) Area of rhombus = ½ * (diagonal1)*(diagonal 2)

Let the ratio be x

Diagonal 1= 2x

Diagonal 2= 3x

147 = ½ * (2x)*(3x)

Multiply both side by 2

294 = (2x)*(3x)

294 = 6x^2

Divide both side by 6

294/6 = 6x^2/6

49 = x^2

x= 7 unit

8 0
3 years ago
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