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Lapatulllka [165]
2 years ago
5

3 qt = ___ gal (it will be a decimal)

Mathematics
1 answer:
melomori [17]2 years ago
6 0

Answer:

.75

Step-by-step explanation:

I know this because 4 quarts = a gallon so if you do 3/4 of a gallon you get .75

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What is the value of s and the length of side BC if ABCD is a rhombus?
Natali5045456 [20]

Step 1

<u>Find the value of s</u>

we know that

In a Rhombus all sides are congruent

so

AB=BC=CD=DA

AB=9s+29\\CD=10s-16

equate AB and CD

9s+29=10s-16\\

Combine like term

10s-9s=29+16\\

s=45\ units

<u>The answer Part a) is</u>

the value of s is 45\ units

Step 2

<u>Find the value of side AB</u>

AB=9s+29

substitute the value of s

AB=9*45+29=434\ units

Remember that the sides are congruent

AB=BC=CD=DA

therefore

<u>the answer Part b) is</u>

The length of the side BC is 434\ units


4 0
3 years ago
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yan [13]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
Can you help me on this one? I kinda forgot this whole unit Lowkey so can you explain it as if there were someone who never lear
DIA [1.3K]

Answer:

here’s something that will help

answer is at the bottom if needed

Step-by-step explanation:

8 0
3 years ago
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Diane serves breakfast to two groups of children at a daycare center. One box of oaties contains 12 cups of cereal.She needs 1/3
IRISSAK [1]
11(1/3)+(3/4)10 = 11/3+30/4
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6 0
3 years ago
Lou has an account with $10,000 which pays 6% interest compounded annually. if to that account, lou deposits $5,000 at the begin
Tems11 [23]

ince the problem is only asking for 4 years, we can just calculated it out year by year. Recall the formula for compounding interest: A = P(1+r)n, where A is the total amount, P is the principle (amount you start with), r is the interest rate per period of time, and n is the number of periods (in this case, r is annual interest rate, so n is number of years). At the beginning (Year 0), Lou starts off with 10000: A = 10000 At the end of Year 1, Lou earned interest on that amount, plus he has deposited another 5000: A = 10000(1.08) + 5000 End of Year 2, Lou's interest from the year 0 amount has compounded, he has started earning interest on the amount deposited last year, and he deposits another 5000: A = 10000(1.08)2 + 5000(1.08) + 5000 End of Year 3, same idea. Lou has earned compounding interest on all existing deposits, and deposits another 5000: A = 10000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 End of Year 4, same idea: A = 10000(1.08)4 + 5000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 = 36135.45



7 0
3 years ago
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