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2 years ago

Find the median and mean of the data set below please!!! 29,8,11,29,29,6,49

Mathematics

1 answer:

g100num [7]2 years ago

4 0

Answer:

See below

Step-by-step explanation:

Mean: $\frac{29+8+11+29+29+6+49}{7}=\frac{161}{7}=23$

Median: $6,8,11,\bold{29},29,29,49$

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Samantha's parents are going to paint her room. Her color choices for the

Phantasy [73]

Answer:the answer will be 6/16

Step-by-step explanation:

3/8

4 0

3 years ago

On a trip to a lake, Kerrie and Shelly rode their bicycles four more than three times as many miles in the afternoon as in the m

Natalija [7]

Answer:

27 miles in the morning and 85 miles in the afternoon.

Explanation:

Let m be the number of miles they rode in the morning. They rode 4 more than 3 times this many in the afternoon; this gives us the expression

3m+4

to represent the miles ridden in the afternoon.

Together they rode 112 miles; this means we add the morning miles, m, to the afternoon miles, 3m+4, and get 112:

m+3m+4 = 112

Combine like terms:

4m+4 = 112

Subtract 4 from each side:

4m+4-4= 112-4

4m = 108

Divide both sides by 4:

4m/4 = 108/4

m = 27

They rode 27 miles in the morning.

That means in the afternoon, they rode

3m+4 = 3(27)+4 = 81+4 = 85 miles.

5 0

3 years ago

Read 2 more answers

the ratio of the number of skiers who bought passes to the number of snowboaders who bought season passes is 1:2 . if 1250 more

viva [34]

If a ratio of skiers and snumboarders is 1:2, and if there are 1250 snowboarders more than skiers, it means that is that there 2500 snowboarders and 1250 skiers.

How to check it? 2500 is 1250 more than 1250 and the ratio is still 1:2 (there are two times more snowboarders than skiers). Both conditions are fulfiled, so it's correct.

3 0

3 years ago

Find the Area of the Shaded Region.

BaLLatris [955]

Area of rectangle is length x width
area of smaller rectangle
9x5=45
area of large rectangle
11x7=77
77-45=32

5 0

3 years ago

Read 2 more answers

use the general slicing method to find the volume of The solid whose base is the triangle with vertices (0 comma 0 ), (15 comma

lyudmila [28]

Answer:

volume V of the solid

$\boxed{V=\displaystyle\frac{125\pi}{12}}$

Step-by-step explanation:

The situation is depicted in the picture attached

(see picture)

First, we divide the segment [0, 5] on the X-axis into n equal parts of length 5/n each

[0, 5/n], [5/n, 2(5/n)], [2(5/n), 3(5/n)],..., [(n-1)(5/n), 5]

Now, we slice our solid into n slices.

Each slice is a quarter of cylinder 5/n thick and has a radius of

-k(5/n) + 5 for each k = 1,2,..., n (see picture)

So the volume of each slice is

$\displaystyle\frac{\pi(-k(5/n) + 5 )^2*(5/n)}{4}$

for k=1,2,..., n

We then add up the volumes of all these slices

$\displaystyle\frac{\pi(-(5/n) + 5 )^2*(5/n)}{4}+\displaystyle\frac{\pi(-2(5/n) + 5 )^2*(5/n)}{4}+...+\displaystyle\frac{\pi(-n(5/n) + 5 )^2*(5/n)}{4}$

Notice that the last term of the sum vanishes. After making up the expression a little, we get

$\displaystyle\frac{5\pi}{4n}\left[(-(5/n)+5)^2+(-2(5/n)+5)^2+...+(-(n-1)(5/n)+5)^2\right]=\\\\\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2$

But

$\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2=\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}((5/n)^2k^2-(50/n)k+25)=\\\\\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)$

we also know that

$\displaystyle\sum_{k=1}^{n-1}k^2=\displaystyle\frac{n(n-1)(2n-1)}{6}$

and

$\displaystyle\sum_{k=1}^{n-1}k=\displaystyle\frac{n(n-1)}{2}$

so we have, after replacing and simplifying, the sum of the slices equals

$\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)=\\\\=\displaystyle\frac{5\pi}{4n}\left(\displaystyle\frac{25}{n^2}.\displaystyle\frac{n(n-1)(2n-1)}{6}-\displaystyle\frac{50}{n}.\displaystyle\frac{n(n-1)}{2}+25(n-1)\right)=\\\\=\displaystyle\frac{125\pi}{24}.\displaystyle\frac{n(n-1)(2n-1)}{n^3}$

Now we take the limit when n tends to infinite (the slices get thinner and thinner)

$\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}\displaystyle\frac{n(n-1)(2n-1)}{n^3}=\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}(2-3/n+1/n^2)=\\\\=\displaystyle\frac{125\pi}{24}.2=\displaystyle\frac{125\pi}{12}$

and the volume V of our solid is

$\boxed{V=\displaystyle\frac{125\pi}{12}}$

3 0

3 years ago