Answer:
its gonna be the second one down on the left!! i can give an explanation if ur having trouble
Step-by-step explanation:
Answer:
B. Centers: the sea turtles have a greater median age than the koi
D. Spreads: the ages of the koi are more spread out
Step-by-step explanation:
The difference between the center and spread of the data distribution of koi and sea turtles as shown in the dot plots are as follows:
==>Median:
For Koi, the median value is the 14th value represented by the 14th dot on the plot, which is 30.
The median value for koi is between the 7th and the 8th value represented by dots on the plot. The average of both values will give us 55 as the median value for koi.
Therefore, the median age of sea turtle is greater than that of koi.
==>Spread:
Koi has a range of 45 (60-15), while sea turtles have a range of 20 (65-45). Invariably, mere looking at the dot plot, we can conclude that ages of the koi are more spread out.
Cora earned $40 and Dora earned $60...label the graph in values of tens and plot accordingly...this might be wrong but I think it’s the best answer
Answer:
0.903264
Step-by-step explanation:
Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.
Let A' = the event that A fails, B' = B fails and C'= C fails.
Probability that no circuit board fails = Prob (A'B'C')
= P(A')P(B')P(C') (since A,B, C are independent, their complements are independent
= (1-0.03)(1-0.04)(1-0.03)
= 0.903264