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Amiraneli [1.4K]

2 years ago

15

9 The circumference of circle B is 90% of the circumference of circle A. (a) Find the ratio of the area of circle A to the area

of circle B.

1 answer:

AfilCa [17]2 years ago

6 0

If the circles circumference is 90% of another circles then the ratio would be 10:9, Circle A would be 10 and Circle be would be 9

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find four consecutive even integers such that 2 times the sum of the first and second is 14 more than 3 times the fourth.

motikmotik

Let the first integer be x, then:-

2 (x + x+ 2) = 3(x + 6) + 14

4x + 4 = 3x + 18 + 14
x = 18 + 14 - 4 = 28

the four integers are 28,30,32 and 34.

8 0

4 years ago

Find the common factor of all the terms of the polynomial below<br><br> 49y^3-7y^2+14y

Alecsey [184]

<span>49y^3-7y^2+14y

= 7y(7y^2 - y + 2)</span>

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3 years ago

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melisa1 [442]

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8 0

4 years ago

Felix’s feed mill sells chicken feed for $8.00 per bag. this price is no longer high enough to create a profit. felix decides to

nydimaria [60]

First, is to raise the price to earn profit. Second, is to maintain the price to maintain the number of buyers. Third, is to maintain the price but to lessen the chicken feed inside a bag. Fourth, to tell the customers first that you will raise the price of your product.

3 0

3 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

4 years ago