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3 years ago

Find the value of z, if it is known that 5+2z is 3 more than 3z−4 Thanks

Mathematics

2 answers:

77julia77 [94]3 years ago

4 0

The answer is 6 I believe

Allushta [10]3 years ago

3 0

Answer: The required value of z is 6.

Step-by-step explanation: Given that 5+2z is 3 more than 3z-4.

We are to find the value of z.

According to the given information, the equation expressing the given statement mathematically can be written and solved as follows:

$5+2z=(3z-4)+3\\\\\Rightarrow 5+2z=3z-1\\\\\Rightarrow 3z-2z=5+1\\\\\Rightarrow z=6.$

Thus, the required value of z is 6.

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A line that includes the points ( - 4, - 3) and ( - 3,S) has a slope of 3. What is the value of s?

Illusion [34]

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-4, -3) and (-3, s) and the slope m = 3. Substitute:

6 0

2 years ago

The circumference of the flotation device above is 62.8 inches . If three flotation devices are lined up end-to-end , then what

Karo-lina-s [1.5K]

Answer: 60 in

Step-by-step explanation:

Hi, to answer this question, first we have to calculate the diameter of one flotation device:

Circumference of a circle C = (3.14) (diameter)

Replacing with the values given:

62.8 =3.14 d

Solving for d (diameter)

62.8 /3.14 =d

20in = d

Now, since the three flotation devices are identical, we simply have to multiply the diameter of one device by 3 , to obtain length of the flotation devices lined up.

20x3 =60 in

Feel free to ask for more if needed or if you did not understand something.

6 0

2 years ago

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.