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pickupchik [31]
2 years ago
14

Rationalize the denominator, then simplify 10/sqrt2

Mathematics
1 answer:
kupik [55]2 years ago
6 0

Answer:

5\sqrt{2}

Step-by-step explanation:

To rationalize the denominator, you need to multiply the numerator and denominator by the radical in the denominator (aka. a factor of 1):

\frac{10}{\sqrt{2}}

\frac{10}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}

\frac{10\sqrt{2}}{2}

5\sqrt{2}

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Which is equivalent to sqrt x^10<br> A. X-5<br> B. X -1/5<br> C. X sqrt 10<br> D. X 1/5<br> E. X^5
Lesechka [4]
<h3>Answer:  E) x^5</h3>

\sqrt{x^{10}} = x^5

=====================================================

Explanation:

We simply take half of the exponent 10 to get 5. This applies to square roots only.

So the rule is \sqrt{a^b} = a^{b/2}

A more general rule is

\sqrt[n]{a^b} = a^{b/n}

If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.

5 0
3 years ago
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74.823 WHAT IS THE PLACE VALUE OF THE 3?
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mestny [16]

Answer:

102.3

Step-by-step explanation:

a_38 = -5

difference d= -2.9

We use general formula

a_n = a_1 + (n-1)d

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Plug in 38 for n

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Now plug in -2.9 for d and -5 for a_38

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