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Pavel [41]
2 years ago
6

Geometry question: What are the coordinates of the image of the point (3, -11) under a dilation with a scale factor of 5 and the

center of dilation at the origin?
Mathematics
1 answer:
Alexxandr [17]2 years ago
7 0

Answer:

The coordinates are (15,-55).

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Step-by-step explanation:

Diagonals of a rhombus are perpendicular bisector.

Hence, triangle ABE so formed would be a right triangle right angled at E.

Therefore, by Pythagoras theorem:

AB =  \sqrt{AE^2 + BE^2 }  \\  \\  \therefore \: AB =  \sqrt{5^2 + 12^2 }  \\  \\  =  \sqrt{25 + 144}  \\  \\  =  \sqrt{169}  \\  \huge \red { \boxed{ \therefore \: AB= 13}}

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Answer:

\boxed{\boxed{B.\ f(x)=\dfrac{3}{4}x^2+2x-5}}

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Quadratic function-

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