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2 years ago

What is the slope of the line through (- 1, - 7) and (3, 9) ?

Mathematics

1 answer:

Fynjy0 [20]2 years ago

5 0

Answer:

C. 4

Step-by-step explanation:

Use the slope formula:

$m=\frac{y2}{x2} -\frac{y1}{x1}$

m = the slope.

Substitute the values into the formula:

$\frac{9}{3} -\frac{-7}{-1} =\frac{?}{?}$

Solve:

$\frac{9}{3} -\frac{-7}{-1} =\frac{16}{4}$

Simplify 16/4:

$\frac{16/4}{4/4} =\frac{4}{1}=4$

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Determine the most specific name for quadrilateral JKLM if the coordinates of the vertices are:J(-4,6), K(-1,2), L(1,6), M(4,2)J

Arturiano [62]

To finish the demonstration that the quadrilateral JKLM is a rhombus we need to prove that side JK is congruent with side LM.

The length of a segment with endpoints (x1, y1) and (x2, y2) is calculated as follows:

$\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}$

Substituting with points L(1,6) and M(4,2) we get:

$\begin{gathered} LM=\sqrt[]{(4-1)^2+(2-6)^2} \\ LM=\sqrt[]{3^2+(-4)^2} \\ LM=\sqrt[]{9+16^{}} \\ LM=5 \end{gathered}$

Given that opposite sides are parallel, all sides have the same length, and, from the diagram, the quadrilateral is not a square, we conclude that it is a rhombus.

5 0

1 year ago

Write an equation of the line containing the point (6,-4) and perpendicular to.the line y=-2x-3

igor_vitrenko [27]

Answer:

$y=\frac{1}{2}x-7$

Step-by-step explanation:

So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.

First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:

$m_1\cdot m_2=-1$

Plug -2 for one of the slopes.

$-2\cdot m_2=-1$

Divide by -2 to find the slope of our line.

$m_2=1/2$

Thus, our line needs to have a slope of 1/2.

Now, let's use the point-slope form. The point-slope form is given by:

$y-y_1=m(x-x_1)\\$

Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:

$y-(-4)=\frac{1}{2}(x-6)\\$

Simplify and distribute:

$y+4=\frac{1}{2} x-3$

Subtract 4 from both sides:

$y=\frac{1}{2}x-7$

The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.

5 0

3 years ago

A ray cannot be perpendicular to a line. true or false? no guesses please

galina1969 [7]

Answer:

TRUE

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Classify the following triangle. Check all that apply.

Vikentia [17]

Answer:

it is an isosceles obtuse triangle.....

you can choose anyone

isosceles ( since two of its sides are equal but not the third)

or obtuse ( since one angle is more than 90)

3 0

3 years ago

Write the percent shown by each model. Explain your reasoning.

Sphinxa [80]

A) 1/3=33 1/3%
B) 2/3=66 2/3%
C) 1/6=16 2/3%

A) YOU CAN TURN THE FRACTION 1/3 INTO A DECIMAL WHICH WILL BE AROUND 0.333. THEN YOU TURN THE DECIMAL INTO A PERCENT. YOU CAN MOVE THE DECIMAL TWO PLACES TO THE RIGHT. THAT GIVES YOU 33.3% OR 33 1/3% THIS ALSO APPLIES TO B BUT WITH 0.666 AND 66.6%

FOR C, YOU DO THE SAME. 1/6 AS A DECIMAL IS 1.666. YOU MOVE THE DECIMAL TWO PLACES TO THE RIGHT. 16.6% OR 16 2/3%

HOPE THIS HELPED.

8 0

3 years ago