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jeka57 [31]
3 years ago
14

Using only pennies, nickels, dimes, and quarters, what is the smallest number of coins Freddie would need so he could pay any am

ount of money less than a dollar?
Mathematics
2 answers:
horsena [70]3 years ago
8 0
Three quarters two dimes four pennies
andriy [413]3 years ago
3 0

Answer:

It depends usually, but if he wanted to pay a dollar he would need to use dimes.

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It's not 0.9158 or w/ the added 5 XP
Yakvenalex [24]

Answer:

go back to hong kong

imma send you back to hong kong

Step-by-step explanation:

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3 years ago
LAST QUESTION....im runing out of points- ANWAYS ✨✨✨ WHAT is you favorite 3 COLORS....mines are yellow light blue and pink​
levacccp [35]

Answer:

navy blue black and marron

Step-by-step explanation:

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3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
Helga [31]

Answer:

\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

a = -2

Taylor series for the function <em>f </em>at the number a is:

f(x) =  \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n

f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ... ............ equation (1)

Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2

f(x) = 10/x            f(-2) = 10/-2

f'(x) = -10/x²         f'(-2) = -10/(-2)²

f"(x) = -10.2/x³      f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴     f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵    f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)

So, we get \sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}} Or \sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

4 0
3 years ago
The equation below describes a parabola. If a is positive, which way does the
Rzqust [24]
B. Up

Because a positive ‘a’ value will make the parabola open upwards, and because the power is 2 (even) both sides will open up in a ‘U’ shape
8 0
2 years ago
Read 2 more answers
Will award brainliest to correct answer!
Artyom0805 [142]

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

\angle \: ABP =  \frac{180 - 80}{2}  = 50 \degree

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

Therefore, the angle BKQ is equal to 180-50-45=85°.

Of course angle BKP=180-85=95°.

Hope this helps :)

6 0
3 years ago
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