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kvasek [131]
4 years ago
6

The product of two negative rational numbers is

Mathematics
2 answers:
solmaris [256]4 years ago
7 0

Answer:

Option 1 - The product of two negative rational numbers is never zero.

Step-by-step explanation:

To find : The product of two negative rational numbers ?

Solution :

By zero product rule,

If a\cdot b=0 either a=0 or b=0 or both are zero.

i.e. the two number product will be zero if any of them is zero.

Now, this case is also valid for negative number as multiply of two negative number is positive.

As zero is not considering to be negative number.

So, the product of two negative rational numbers is never zero.

Therefore, option 1 is correct.

Mkey [24]4 years ago
4 0
Always zero because it stays the same
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For the function f(x) = 7/2x-16, what is the difference quotient for all nonzero values of h?
sergey [27]

Answer:

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}

Step-by-step explanation:

Given

f(x) = \frac{7}{2}x - 16

Required

The difference quotient for h

The difference quotient is calculated as:

\frac{f(x + h) - f(x)}{ h}

Calculate f(x + h)

f(x) = \frac{7}{2}x - 16

f(x+h) = \frac{7}{2}(x+h) - 16

f(x+h) = \frac{7}{2}x+ \frac{7}{2}h- 16

The numerator of \frac{f(x + h) - f(x)}{ h} is:

f(x + h) - f(x) =  \frac{7}{2}x+ \frac{7}{2}h- 16 -(\frac{7}{2}x - 16)

f(x + h) - f(x) =  \frac{7}{2}x+ \frac{7}{2}h- 16 -\frac{7}{2}x + 16

Collect like terms

f(x + h) - f(x) =  \frac{7}{2}x  -\frac{7}{2}x + \frac{7}{2}h- 16 + 16

f(x + h) - f(x) = \frac{7}{2}h

So, we have:

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h \div h

Rewrite as:

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h * \frac{1}{h}

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}

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