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iogann1982 [59]

2 years ago

7

A 17-meter piece of string is stretched from the top of a 15-meter flagpole to the ground. How far is the base of the flagpole f

rom the end of the piece of string?
show work

1 answer:

lord [1]2 years ago

3 0

Answer:

c2=a2+b2 1. 172=square +b2 289=225+b2 2.

please mark as brainliest

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Please help will give brainliest please

lyudmila [28]

Answer:

20

Step-by-step explanation:

10 is equal to the side infront of it. 10 +10 = 20

rounding it to the nearest degree will also be 20

8 0

3 years ago

C= 2 7r; for r<br> Plzz help

Nutka1998 [239]

Answer:

$C/27=r$

Step-by-step explanation:

$C= 2 7r$

$C \div 27= 2 7r \div 27$

$C/27=r$

5 0

3 years ago

Read 2 more answers

Lines e and f are parallel. The mAngle9 = 80° and mAngle5 = 55°. Parallel lines e and f are cut by transversal c and d. All angl

brilliants [131]

Answer:

$(A)m\angle 2=125^\circ\\(C)m\angle 8=55^\circ\\(E)m\angle 14=100^\circ$

Step-by-step explanation:

The diagram of the problem is drawn and attached.

Given that:

$m\angle 9 =80^\circ\\m\angle 5 =55^\circ$

$m\angle 5+ m\angle 6=180^\circ\\55^\circ+ m\angle 6=180^\circ\\m\angle 6=180^\circ-55^\circ\\m\angle 6=125^\circ\\$Now:\\m\angle 6 = m\angle 2 $(Corresponging angles)\\Therefore m\angle 2=125^\circ\\$

$m\angle 5= m\angle 8=55^\circ $(Vertically Opposite Angles)$

Also

$m\angle 9+ m\angle 10=180^\circ\\80^\circ+ m\angle 10=180^\circ\\m\angle 10=180^\circ-80^\circ\\m\angle 10=100^\circ\\$Now:\\m\angle 10 = m\angle 14 $(Corresponging angles)\\Therefore m\angle 14=100^\circ\\$

4 0

3 years ago

Read 2 more answers

HELP MEEEEE EASY DUE IN A MINSS<br> What is the prime factorization of 990?

alex41 [277]

Answer:

11 is one of the factors! The orange divisor(s) above are the prime factors of the number 990. If we put all of it together we have the factors 2 x 3 x 3 x 5 x 11 = 990.

Step-by-step explanation:

3 0

3 years ago

In a certain game, a player can solve easy or hard puzzles. A player earns 30 points for solving an easy puzzle and 60 points fo

Aleksandr-060686 [28]

Answer: Second option.

Step-by-step explanation:

Let be "e" the number of easy puzzles Tina solved and "h" the number of hard puzzles Tina solved.

Set up a system of equations:

$\left \{ {{e+h=50} \atop {30e+60h=1,950 }} \right.$

You can use the Eliminationn Method to solve this system of equations:

Multiply the first equation by -30.
Add the equations.
Solve for "h".

Therefore, through this proccedure, you get:

$\left \{ {-30e-30h=-1,500} \atop {30e+60h=1,950 }} \right.\\.........................\\30h=450\\\\h=\frac{450}{30} \\\\h=15$

6 0

3 years ago