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3 years ago

15

Shadow software company earned a total of 800,000 selling programs during the year 2012. 125,300 of that amount was used to pay

expenses of the company .How much profit did shadow software company make in the year 2012?

1 answer:

MissTica3 years ago

3 0

800,000-125,300= 674700 hope i helped pls make me brainliest

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If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

<u><em>Solved</em></u>

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2 years ago

3 (x - 3) + x (r + 4)

docker41 [41]

Answer:

Step-by-step explanation:

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3 years ago

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liq [111]

The measure of a right angle is 90 degrees

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3 years ago

I need help, I don't know how to do it.

Sindrei [870]

Answer:

Step-by-step explanation:

to solve this problem we can use the Pythagorean theorem

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We have to find LU so we can proceed like this

x^2 + (x+1)^2 = LU^2

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2 years ago

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lora16 [44]

$\bf \cfrac{x^2+6x-9}{x-2}\qquad 
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if the degree of the expression of the numerator is greater than that of the denominator, the rational expression has no horizontal asymptote.

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