Given that median area is 15 square units.
Hence rectangle C in the middle has 15 square units.
Its dimensions can be width= 5 and length = 3
SInce B is smaller than C and has the same length, B has lengh of 3 with area = 9 sq units.
D has the same perimeter = 16 units. Since D is a square, side of D = 4 units.
Now D and E have the same length. Hence length of E = 4 units.
Width of E = width of C = 5 units.Thus makes the area of E as 20 sq units.
Rectangle A has length =3 and width can be less than 3 since area is smaller than B.
so A has length= 3 width = 2 with area = 6 sq units.
Answer: A) Yes, it is a solution.
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Explanation:
Replace every x with -3 and simplify both sides.
3x - 2 < 2 - 2x
3(-3) - 2 < 2 - 2(-3)
-9 - 2 < 2 + 6
-11 < 8
Since -11 is to the left of 8 on the number line, this means the inequality -11 < 8 is true. Consequently, it means the first inequality is true when x = -3.
Therefore, x = -3 is a solution.
Answer:
Step-by-step explanation:
