Question

1. A spinner is divided into six equally sized regions. Two of the regions are labeled 6, two of the regions are labeled 2, one region is labeled 1, and the last region is labeled 3. The spinner is spun 750 times.
(a) How many times is the spinner expected to land on 6?
(b) How many times is the spinner expected to land on a prime number?

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Answer 1

Answer:

a) 250

b) 125

Step-by-step explanation:

For a, the answer is 250 because if 2 regions are labelled 6, and there are 6 regions, and the spinner is spun 750 times, then we will multiply 2 by 750 and divide the answer by 6.

2 x 750 = 1500

1500/6 = 250

Now, for b, the answer is 125 because 3 is the only prime number there and only one region is labelled 3. So we multiply 1 by 750 (which is 750) and divide by 6.

750/6 = 125.

a = 250

b = 125