Answer:
7
Step-by-step explanation:
If the ratio is 2:3:2 that means that there is 2Karen tomato juice bottles, 3pineapple juice bottles and 2 grape juice bottles you just have to find the sum and get 7juice bottles
Answer:
y = -4x - 7
Step-by-step explanation:
we use the slope intercept formula given by; y = mx + b
b = y intercept, which is when x = 0
m = slope
so they tell us the slope.. we just need to find b - the y intercept.
y = mx + b
plug in your coordinates (-2,1)
1 = -4(-2) + b
1 = 8 + b
1 - 8 = b
-7 = b
put it all together.
y = -4x - 7
B the set of input values for the function.
Answer:
16 13 13 11 11 9 9 8 Median = 11 Mean = 11.25
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
