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choli [55]
2 years ago
7

PLEASE help! BRAINLIEST to correct answer!

Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
3 0

Step-by-step explanation:

sec(x) = 1/cos(x)

and therefore, it behaves accordingly.

the minimum of cos(x) is the maximum of 1/cos(x).

it does not have any x-intercepts. for cos(x) = 1 (max) we get 1/1 = 1 for sec(x), which is the minimum.

mirrored to this, cos(x) = -1 gives us also -1 for sec(x).

sec(x) = 1/cos(x) can never have a result between -1 and +1.

cos(0) = 1, so also sec(x) = 1, and therefore (0, 1) is the y-axis intercept.

at every pi (beginning at 0) there is a horizontal tangent, but not an asymptote. the (vertical) asymptotes happen at every pi beginning at pi/2 and -pi/2.

therefore, only the third and fourth answer options are correct.

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In front of a store, there is a row of parking spaces. Cars park parallel to one another, with the front of each car facing the
Gelneren [198K]

The width used for the car spaces are taken as a multiples of the width of

the compact car spaces.

Correct response:

  • The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>

Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.

We have;

Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)

New space design = 16·x + 9×(a·x) = x·(16 + 9·a)

When the dimensions of the initial and new arrangement are equal, we have;

10 + 12·a = 16 + 9·a

12·a - 9·a = 16 - 10 = 6

3·a = 6

a = 6 ÷ 3 = 2

a = 2

Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;

10 + 12·a < 16 + 9·a

Which gives;

x·(10 + 12·a) < x·(16 + 9·a)

Therefore;

The initial total car park space is less than the space required for 16

compact spaces and 9 full size spaces, therefore; the store owners are

incorrect.

Learn more about writing expressions here:

brainly.com/question/551090

5 0
2 years ago
Calvin's school is 2.3 miles directly south of his house. After school, he takes a bus 1.8 miles directly west to the sports com
VladimirAG [237]

Answer:

2.9 miles

Step-by-step explanation:

If you draw this as a diagram, you will see that it is a right angled triangle and the missing side is the hypotenuse (the longest side). To calculate this, you will need to use the right angle law:

a^{2} + b^{2} = c^{2}

check out the document below (sorry, it's a little bit blurry)

3 0
3 years ago
A wall has an area of 40 square feet. Its height is 8 feet. Which equation could you use to find its width?
lord [1]

Answer:

40/8=5

Other side length = 5

Step-by-step explanation:

7 0
2 years ago
The height, h, of the equilateral triangle is given by h =5cotΘ, where Θ is 30 degrees. Can someone help me with this? I don't u
Hoochie [10]

You don't even need the picture to solve this one.

You said that      h = 5 cot(Θ) ,    and you said that  Θ  is 30 degrees.
All you need now is to find the cotangent of  Θ, plop that into the equation,
and the solution practically jumps off the paper into your lap.

To find the cotangent of 30 degrees, you can use a calculator, look it up
in a book, read it off of a slide rule if you have one, draw a picture of a
30-60-90 right triangle etc.  You'll find that the cotangent of 30 degrees
is  √3 .  That's about 1.732 .

So your equation is    h = 5 (1.732)  =  <em>8.66  </em>(rounded)

Apparently, somebody gave you the equation, and asked you to find 'h'.
Once you had the equation, you didn't even need to know that  'h'  has
anything to do with a triangle.


5 0
3 years ago
Given that f(x) = 2x2 − 96, find x.
NISA [10]
F(x)=2x(2)−96

Step 1: Add -4x to both sides.

xf+ −4x = 4x−96+ −4x

xf −4x= −96

Step 2: Factor out variable x.

x(f−4)= −96

Step 3: Divide both sides by f-4.

x(f−4)/ f−4 = −96/ f−4

x= −96/f−4

Answer:

x= −96/ f−4

3 0
3 years ago
Read 2 more answers
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