The slope intercept form of the line whose points are (1,5) and (-2,-4) is y=3x+2.
Given two points of a line (1,5) and (-2,-4).
We have to form an equation in slop intercept form.
Equation is relationship between two or more variables which are expressed in equal to form.Equations of two variables looks like ax+by=c.
Point slope form of an equation is y=x+mc where m is slope of the line.
From two points the formula of equation is as under:
(y-
)=
*(x-
)
where 
are the points.
Putting the values of =1, 
=-2, =5 and 
=-4.
y-5=(-4-5/-2-1)*(x-1)
y-5=-9/-3*(x-1)
y-5=3(x-1)
y-5=3x-3
y=3x-3+5
y=3x+2
Hence the slope intercept form of the line having points (1,5)(-2,-4) is y=3x+2.
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Answer:
x-3
Step-by-step explanation:
f(x) = 3x – 2
g(x) = 2x + 1
(f – g)(x) = 3x-2 - ( 2x+1)
Distribute the minus sign
= 3x-2 -2x -1
= x -3
We want to use substitution to solve
-5x + 4y = 22 (1)
x - 3y = 0 (2)
From (2), obtain
x = 3y (3)
Substitute (3) into (1).
-5(3y) + 4y = 22
-15y + 4y = 22
-11y = 22
y = -2
From (3), obtain
x = 3y = 3*(-2) = -6
Answer: e. (-6, -2)
Answer:
hope it helps you.............!
Answer: 25x² - 64
<u>Step-by-step explanation:</u>
(5x + 8)(5x - 8)
= 5x(5x - 8) + 8(5x - 8)
= 25x² - 40x + 40x - 64
= 25x² + 0x - 64
= 
NOTE: descending powers means the biggest exponent goes first, then the next biggest exponent, etc.
For example: x⁴ then x³ then x² then x then the number (which is actually x⁰)
