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2 years ago

I need help it’s kinda hard

Mathematics

1 answer:

viva [34]2 years ago

4 0

No because 2/5 is not equal to 1/3

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Can you explain this to me I have no idea

kap26 [50]

Step-by-step explanation:

number 2... write the equation then balance as shown above...don't forget the state symbols

8 0

2 years ago

the tama japan monorails carries 92700 riders each day if the monorails runs 18 hour each what is the average number of passenge

Bas_tet [7]

In 18 hours = 92700

In 1 hour it would be: 92700/18 = 5150 riders

3 0

3 years ago

Read 2 more answers

A person has to walk 100 m to go from position X in the north of east direction to the position B and then to the west of Y to r

aleksandrvk [35]

Answer:

The distance between X and Y is 68m

Step-by-step explanation:

Consider the diagram attached:

A person starts from X, goes to Y, and then finally goes to Z, covering a total of 100m, where Z is located 60m in north of X.

We have to find distance XY.

Let the distance XY be x

Total distance covered by the person = XY + YZ

We know that total distance covered is 100m, so

100m = x + YZ

YZ = (100 - x)m

See the diagram, XZY forms a right angled triangle such that:

Hypotenuse = XY = x

Base = XZ = 60m

Perpendicular = YZ = (100-x)m

Using Pythagoras theorem

Hypotenuse² = Base² + Perpendicular²

x² = (60)² + (100-x)²

Solve the equation for x, we get:

x = 68m

6 0

3 years ago

NEED ASAP!!!!<br><br> Find the GCF of 72 60 120. show all work!

kari74 [83]

Answer: 12

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

The factors of 120 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Then the greatest common factor is 12

7 0

3 years ago

Find the volume of the solid in the first octant (x ≥ 0, y ≥ 0, z ≥ 0) bounded by z = 8 - x², z = x², and y = 3.

vampirchik [111]

Setting up and computing the integral is straightforward. The two parabolic cylinders $z=8-x^2$ and $z=x^2$ meet when

$x^2 = 8 - x^2 \implies 2x^2 = 8 \implies x = \pm2$

Then the volume is

$\displaystyle \int_0^3 \int_{-2}^2 \int_{x^2}^{8-x^2} dz \, dx \, dy = 3 \int_{-2}^2 ((8-x^2) - x^2) \, dx \\\\ ~~~~~~~~ = 6 \int_0^2 (8 - 2x^2) \, dx = \boxed{64}$

3 0

1 year ago