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2 years ago

14

-1(3a-2) I NEED the answer to this one

2 answers:

weeeeeb [17]2 years ago

4 0

Answer:

-3a+3

Step-by-step explanation:

Your answer should be -3a+3

Sophie [7]2 years ago

3 0

Your answer would be -3a+2 !! ^^

step one:
any expression multiplied by one stays the same

step two:
when there is a (-) in front of an expression in parentheses, change the sign of each term of the expression and remove the parentheses

step three:
your answer after all that would be -3a+2 !!

hope that helps you out :D

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Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$f(x) = x^{2} + 3x - 1$

So

$a = 1, b = 3, c = -1$

$\bigtriangleup = 3^{2} - 4*1*(-1) = 13$

$x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3$

$x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3$

The real zeros of f(x) are x = 0.3 and x = -3.3.

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