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2 years ago

Solve for V please I can´t figure it out 40+4.5v=67

Mathematics

2 answers:

Inessa [10]2 years ago

7 0

Answer:

Step-by-step explanation:

The first step for this problem is to get the term with v by itself:

40+4.5v = 67

4.5v = 67-40

4.5 v = 27

Now divide 27 by 4.5 to fully isolate v:

v = 27/4.5 = 6

Delvig [45]2 years ago

6 0

Answer:

Step-by-step explanation:

subtract 40 from both sides

divide both sides by 4.5

you're left with v equals 6

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Simplify the expression 4 squaere root of 9

nlexa [21]

Answer:

Step-by-step explanation:

4 / sqrt {9}

4(3)

4 x 3

7 0

2 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

4 years ago

What is the value of the remainder if 10x4 – 6x3 + 5x2 – x + 1 is divided by x – 3?

natita [175]

Answer:

Remainder is 691.

Step-by-step explanation:

Given function is $10x^4-6x^3+5x^2-x+1$ .

Now we need to find remainder if we divide given function $10x^4-6x^3+5x^2-x+1$ by (x-3)

(x-3) means plug x=3 into $10x^4-6x^3+5x^2-x+1$ to find remainder.

$10x^4-6x^3+5x^2-x+1$

$=10(3)^4-6(3)^3+5(3)^2-(3)+1$

$=10(81)-6(27)+5(9)-(3)+1$

$=810-162+45-3+1$

$=856-162-3$

$=856-165$

$=691$

Hence remainder is 691.

8 0

3 years ago

Read 2 more answers

140 degrees decreased by 65%

BaLLatris [955]

Hey there!
Here are the steps involved:

1.Change 65% into a decimal. Move the decimal two places to the left and you get 0.65.

2. Multiply 0.65 by 50.
140 x 0.65 = 91.

3. Since you are decreasing 140 by 65%, subtract 140 by 91.
140-91= 49

(If you feel that my answer has helped you, please consider rating it and giving it a thank you! Also, feel free to make the best answer, the brainliest answer!)

Thank you! :D

7 0

3 years ago

Plz answer i will really apreciate it :) 50 points

hoa [83]

Answer:

b or c

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers